Question 1011144

 {{{(x-1/x)/(1-1/x^2 )}}}


={{{((x^2-1)/x)/((x^2-1)/x^2 )}}}


={{{(x^2(x^2-1))/(x(x^2-1) )}}}


={{{(x^cross(2)cross((x^2-1)))/(cross(x)cross((x^2-1)) )}}}


={{{x}}}


so, answer is A. {{{x}}}