Question 1011113

He has {{{4}}} more quarters than dimes:
{{{q=d+4}}}
 and {{{3}}} more dimes than nickels:
{{{d=n+3}}}

If {{{n}}} represents the number of nickels he has, then he has {{{(n+3)}}} dimes, and {{{((n+3)+4)=(n+7)}}}quarters.

The total value of all his coins is:

 {{{5*n+10*(n+3)+25*(n+7)=5n+10n+30+25n+175=40n+205}}}

Answer: A. {{{40n+205}}}