Question 1011117
let x and y be the two numbrs.


the sum of the cubes of the two numbers = x^3 + y^3.


the cube of the sum of the two numbers = (x + y)^3 = (x+y) * (x+y) * (x+y).


the difference between the cube of two numbers = x^3 - y^3.


the cube of the difference between two numbers = (x-y)^3 = (x-y) * (x-y) * (x-y)


for example:


if the two numbers are 5 and 3, then:


the sum of the cubes of the two numbers is 5^3 + 3^3 = 125 + 27 = 152.


the cube of the sum of the two numbers is (5+3)^3 = 8^3 = 512.


the difference between the cube of the numbers is 5^3 - 3^3 = 125 - 27 = 98.


the cube of the difference between the numbers is (5-3)^3 = 2^3 = 8.