Question 86648
Given one of the zeros (x = -1), find the other zeros of:
{{{P(x) = x^3 - 6x^2 + 3x + 10}}} First, if x = -1 then x+1 = 0 and this is one of the three solutions to this equation.
Divide the quadrinomial by (x+1) to get {{{x^2-7x+10}}}.  
Now factor this quadratic to get {{{(x-2)(x-5)}}}.
These are the other two solutions, so...
{{{x = 2 and x = 5}}} are the other zeros.