Question 1011072
In a collection box, there are dimes and nickels whose total value is $30. There are 300 more nickels then dimes. How many coins 
of each kind are in the collection box? 
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Value EQ: 5n + 10d = 3000 cents
Quantity:: n = d + 300
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Modify:
n + 2d = 600
n -  d = 300
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Subtract and solve for "d":
3d = 300
# of dimes = 100
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Cheers,
Stan H.
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