Question 86642
Check by plugging (a=-14/15) back into the original equation and solve:
{{{(3a/7)}}}= {{{(-2/5)}}}
{{{(3(-14/15)/7)}}} = {{{(-2/5)}}}
{{{((-14/5)/(7))}}} = {{{(-2/5)}}}
{{{((7/1)(-14/5)/(7))}}}= {{{((7/1)(-2/5))}}}  [multiply each side by the reciprocal of (1/7)]
{{{(-14/15)}}} = {{{(-14/15)}}} [checks out]