Question 1011046
{{{x>=-5}}} whatever is found.


{{{(sqrt(x+5))^2=x^2+6x+9}}}
{{{x+5=x^2+6x+9}}}
{{{x^2+5x+4=0}}}
{{{(x+1)(x+4)=0}}}


<s>And both of these will work as OR</s>:
{{{x=-1}}}  OR  {{{cross(x=-4)}}}


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My mistake.  One should check to see if any solutions fail in the original equation.  x=-4 will not work.