Question 1011037
Let {{{ x }}} = ml of pure acetic acid to be added
{{{ .02*100 = 2 }}} ml of pure acetic acid in 2% solution
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{{{ ( x + 2 ) / ( x + 100 ) = .08 }}}
{{{ x + 2 = .08*( x + 100 ) }}}
{{{ x + 2 = .08x + 8 }}}
{{{ .92x = 6 }}}
{{{ x = 6.522 }}}
6.522 ml of pure acetic acid should be added
check:
{{{ ( 6.522 + 2 ) / ( 6.522 + 100 ) = .08 }}}
{{{ 8.522 / 106.522 = .08 }}}
{{{ 8.522 = 8.522 }}}
OK