Question 1011027
I'll give it a shot, but it's a 
little hard to follow
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Let {{{ s }}} = the speed of the slower bus in mi/hr
{{{ s + 10 }}} = the speed of the faster bus in mi/hr
Let {{{ d }}} = the distance between the towns in miles
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Equation for the faster bus:
(1) {{{ d = ( s + 10 )*3.5 }}}
Equation for the slower bus:
(2) {{{ (1/6)*d = s*3.5 }}}
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(1) {{{ d = 3.5s + 35 }}}
and
(2) {{{ d = 21s }}}
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{{{ 21s = 3.5s + 35 }}}
{{{ 17.5s = 35 }}}
{{{ s = 2 }}}
{{{ s + 10 = 12 }}}
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(2) {{{ d = 21s }}}
(2) {{{ d = 21*2 }}}
(2) {{{ d = 42 }}}
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The speed of the slower bus was 2 mi/hr
The speed of the faster bus was 12 mi/hr
The distance between A and B was 42 mi
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check:
(1) {{{ d = ( s + 10 )*3.5 }}}
(1) {{{ d = ( 2 + 10 )*3.5 }}}
(1) {{{ d = 42 }}}
OK
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These numbers are a little strange -check my math