Question 1010890
The vertex form is y=a(x-h)^2+k, where the vertex is (h,k)

That means y=a(x-2)^2+6
Now, use the point given to solve for a.
-1=a(2)^2+6, (x-2)^2=2^2, if x=4
-1=4a+6
4a=-7
a=(-7/4)
(-7/4){x^2-4x+4)+6=
-(7/4)x^2+7x-7+6=-(7/4)x^2+7x-1
{{{graph(300,300,-10,10,-10,10,-(7/4)x^2+7x-1)}}}