Question 1010717
 identify the conic section if it is a parabola give the vertex if it is a circle give the center and radius if it is a ellipse or a hyperbola give the center and foci 
y^2-3x+10y+37=0 
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3x = y^2+10y+37
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x = (1/3)(y^2+10y+37)
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Vertex occurs when y = -b/(2a) = -(10/3)/(2(1/3)) = -5
Then x = (1/3)(25-50+37) = (1/3)(12) = 4
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Vertex (4,-5)
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Cheers,
Stan H.
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