Question 1010642
I see no one has answered this, because you need to submit them one at a time.  I will do the first one...please resubmit the others.
Call the numbers x and y. Then we have
x = y - 3
We also have
xy = 88
Now we substitute and get
(y - 3)y = 88 
y^2 - 3y - 88 = 0
(y - 11)(y + 8) = 0
y = 11 and x = 8
or
y = -8 and x = -11