Question 1010869
From
f(x) = 6x^3 + 3
y = 6x^3 + 3
x = 6y^3 + 3
x - 3 = 6y^3
y^3 = (x - 3)/6
y = [(x-3)/6]^(1/3)
f^(-1)(x) =  = [(x-3)/6]^(1/3)