Question 1010770
a plane is at {{{X}}}({{{5}}},{{{-2}}}) and it has to travel to either {{{Y}}}({{{-2}}},{{{6}}}) or {{{Z}}}({{{9}}},{{{8}}})

to find out which point is closer, find the distance {{{XY}}} and {{{XZ}}} 


*[invoke Distance_Formula_for_Coordinate_Plane 5, -2, -2, 6] 


*[invoke Distance_Formula_for_Coordinate_Plane 5, -2, 9, 8] 


the distance {{{XY=10.6}}}

and the distance {{{XZ=10.8}}}

shorter is the distance {{{XY=10.6}}} by {{{0.2}}}