Question 1010708

the perimeter of a rectangle is {{{P=66m}}}. 

the width {{{W}}} of the rectangle is {{{9m}}} less than the length {{{L}}}:

{{{L=W+9m}}}


{{{P=2L+2W}}}.....substitute {{{L}}}

{{{66m=2(W+9m)+2W}}}

{{{66m=2W+18m+2W}}}....all terms divide by {{{2}}}

{{{33m=W+9m+W}}}

{{{33m-9m=2W}}}

{{{24m=2W}}}

{{{24m/2=W}}}

{{{highlight(W=12m)}}}

now find {{{L}}}

{{{L=12m+9m}}}

{{{highlight(L=21m)}}}