Question 86496
x^2-3x=-6x-1
x^2-3x+6x+1=0
x^2+3x+1=0
using the quadratic equation we get:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
x=(-3+-sqrt[3^2-4*1*1])/2*1
x=(-3+-sqrt9-4])/2
x=(-3+-sqrt5)/2
x=(-3+-2.24)/2
x=(-3+2.24)/2
x=-.76/2
x=-38 answer.
x=(-3-2.24)/2
x=-5.24/2
x=-2.62 answer.