Question 86545
{{{2(a^2b^3c)^2}}}


{{{2(a^2b^3c)(a^2b^3c)}}} Expand

Start with the given expression


{{{2(a^2b^3c)(a^2b^3c)}}}


When you multiply common bases with exponents, you add the exponents



{{{2a^(2+2)b^(3+3)c^(1+1)}}}  Add the exponents  (note: the variables and exponents of the 2nd parenthesis now equal 1. So we don't need to bother with writing them out)


{{{2a^4b^6c^2}}}


So the expression


{{{2(a^2b^3c)^2}}}


simplifies to


{{{2a^4b^6c^2}}}


which really looks like 


{{{2aaaabbbbbbcc}}} note: there are 4 a's, 6 b's, and 2 c's


so the answer is d)