Question 86546
Start with the given expression


{{{(2x^3y)(4x^2y^3)}}}


When you multiply common bases with exponents, you add the exponents



{{{(2x^(3+2)y^(1+3))(4)}}}  Add the exponents  (note: the variables and exponents of the 2nd parenthesis now equal 1. So we don't need to bother with writing them out)


{{{(2x^5y^4)(4)}}}



{{{(8x^5y^4)}}} Now multiply {{{2}}} and {{{4}}} to get {{{8}}}


So the expression


{{{(2x^3y)(4x^2y^3)}}}


simplifies to


{{{(8x^5y^4)}}}


So the answer is d)