Question 1010423

let one no. be {{{x}}} and another no. {{{y}}}

if {{{x}}} is {{{40}}} more than {{{y}}}, we have {{{x=y+40}}}...eq.1

if their sum is {{{50}}}, we have:

{{{x+y=50}}}....eq.2...substitute {{{x}}} from eq.1

{{{y+40+y=50}}}......solve for {{{y}}}

{{{2y+40=50}}}

{{{2y=50-40}}}

{{{2y=10}}}

{{{y=10/2}}}

{{{highlight(y=5)}}}

go back to eq.1 and substitute {{{5}}} for {{{y}}}

{{{x=5+40}}}...eq.1

{{{highlight(x=45)}}}

so, your numbers are: {{{highlight(5)}}} and {{{highlight(45)}}}