Question 1010246


Set up your equations then add:

x²+y² = 25
x²-y² = 7 
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2x² = 32


Solve 2x² = 32 by dividing both sides by 2:

2x²/2 = 32/2

x² = 16

x = 4


Substitute x = 4 into the first equation to obtain the y value:

x²+y² = 25

(4)²+y² = 25

16+y² = 25

y² = 25 - 16

y² = 9

y = 3 


Since x = 4 and y = 3, the two positive numbers are 4 and 3.


Verify:

4²+3² = 25 => 16+9 = 25

4²-3² = 7  => 16 - 9 = 7