Question 1010403
The sum of the interior angles of a polygon with {{{n}}} sides/angles is
{{{(n-2)180^o}}} ,
so the sum of the {{{6}}} interior angles of a hexagon is
{{{(6-2)*180^o=4*180^o=720^o}}} .
The four given angles add up to
{{{130^o+160^o+112^o+80^o=482^o}}} ,
so the sum of the remaining {{{6-2=4}}} angles is
{{{720^o-482^o=238^o}}} .
That means that each of the remaining "equal" angles measures
{{{238^o/2=highlight(119^o)}}} .