Question 1010325


A). {{{5x/x^3 }}}

B). {{{(x^2+3x)/x^3}}} 

C). {{{(4x+12)/(6x+18)}}}

D). {{{(2x+7)/(x+3)}}}


 For 
A). I got {{{5/x^2}}}->{{{correct}}}
 
For B). I got {{{(x^4+3)/x^2}}} ->{{{incorrect}}}
{{{(x^2+3x)/x^3}}}=>{{{(cross(x)(x+3))/x^cross(3)^2}}}=>{{{(x+3)/x^2}}}

For C). I got {{{6x+18}}}->{{{incorrect}}} 

{{{(4x+12)/(6x+18)}}}=>{{{cross(4)2cross((x+3))/cross(6)3cross((x+3))}}}=>{{{2/3}}}
and 
for D). I got {{{(2x^2+3x+7)/x}}}.->{{{incorrect}}}  

{{{(2x+7)/(x+3)}}} is already in simplest form