Question 1010291
(x^2-1)/(3x^2+5x+2) * (x^2-4x-5)/(x^2+6x-7), inverting first.
factor everything possible.
(x+1)(x-1)/(3x+2)(x+1) * (x-5)(x+1)/(x+7)(x-1)=
after cancelling, (x+1)(x-5)/(3x+2)(x+7)
That is c.