Question 1010262
Call the bigger, x, and the smaller, y.
Then we have
3y + x = 63  and
2x - 5y = 16
Solve the first for x and substitute into the second...we get
x = 63 - 3y
and
2(63 - 3y) - 5y = 16
126 - 6y - 5y = 16
-11y = -110
y = 10
x = 63 - 3(10) = 33