Question 1010227
We factor
{{{x^2-3x-10=0}}}
into binomial factors, looking for two numbers that multiply to make ten but have a difference of 3...5 and 2 are the numbers...since the middle term is -3, we know that our factoring has to have -5, like this...
{{{(x - 5)(X + 2) = 0}}}
Then
x = 5 or x = -2