Question 1010202
Write the standard form of the equation of the line described. 
Through; (-4,-5) perp to {{{y=expr(-4/7)x-2}}}
<pre>
Take the {{{-4/7}}}
Change its sign. Get {{{4/7}}}
Invert it. Get {{{7/4}}}
Write {{{y=expr(7/4)x+b}}}
Substitute x=-4 and y=-5
{{{-5=expr(7/4)(-4)+b}}}
-5=-7+b
2=b

Substitute 12 for b in {{{y=expr(7/4)x+b}}}, get {{{y=expr(7/4)x+2}}}.

If we draw the graphs of each, we get what is below.  The red line is 
the graph of the given equation, and the green one is the line through 
(-4,-5) which is perpendicular to it.

{{{drawing(400,400,-10,10,-10,10,circle(-4,-5,.2),locate(-4,-5,"(-4,-5)"), graph(400,400,-10,10,-10,10,(-4/7)x-2,(7/4)x+2)   )}}}

Edwin</pre>