<PRE><B>Question 1010026</B>
x = part invested at 12%.
y = part invested at 8%.


interest on x = .12x
interest on y = .08y


at the end of the year .12x = .08y


x + y = 2000


several ways to solve.
this is one way.


from .12x = .08y, solve for y to get y = .12x/.08 = 1.5x


in x + y = 2000, replace y with 1.5x to get x + 1.5x = 2000


combine like terms to get 2.5x = 2000


solve for x to get x = 2000 / 2.5 = 800.


since x + y = 2000, y must be equal to 1200


.12*800 = 96


.08*1200 = 96


the interest is equal so the solution is confirmed to be good.


jill invested 800 at 12% and 1200 at 8%.





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