Question 1010079
-10t^2+82t+103,
The object will be 200 meters high twice, once going up, and once going down.
-10t^2+82t+103=200
10t^2-82t+97=0 moving and multiplying everything by (-1)
t=(1/20)*{82+/- sqrt (6724-3880)}, the sqrt =53.33
t=(1/20)*135.33=6.7665 sec
t=(1/20)*27.67=1.3835 sec
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h=0 when it hits the ground
-10t^2+82t+103=0; 10t^2-82t-103=0
t=(1/20)* {82+/- sqrt (6724+4120); sqrt (10844)=104.13
use positive value only
t=(-1/20)*186.13=9.3 sec.
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maximum height t=-b/2a, and that is -82/-20 or at 4.1 seconds.
h(4.1)=-168.1+336.2+103=271.1 m
{{{graph(300,300,-10,10,-10,350,-10x^2+82x+103)}}}