Question 1010090


{{{P(x) = 0}}} has the given roots.

{{{x[1] = -2}}}  , {{{ x[2] = 6}}}


{{{P(x) = (x-x[1])(x-x[2])}}}

{{{P(x) = (x-(-2))(x-6)}}}

{{{P(x) = (x+2)(x-6)}}}

{{{P(x) = x^2-6x+2x-12}}}

{{{P(x) = x^2-4x-12}}}


{{{ graph( 600, 600, -10, 10, -10, 10, x^2-4x-12) }}}