Question 86457
Let x=one integer
1/2 of one integer=(1/2)(x) or x/2
Then x+1=next consecutive integer
3/5 of the next consecutive integer=(3/5)(x+1)

Now we are told that:


(3/5)(x+1)-x/2=3  multiply each term by 10 to get rid of fractions
(Note:  (3/5)(x+1) is one term.  When we multiply it by 10, we get:(3/5)(10)(x+1) and this equals {{{((3)(10)/5)(x+1)}}} and this equals {{{((3)(2))(x+1)}}} and this equals 6(x+1))

6(x+1)-5x=30  get rid of parens

6x+6-5x=30  subtract 6 from both sides

x=24--------------------------------one integer

x+1=24+1=25------------------------------------next consecutive integer

CK


6x+6-6-5x=30-6  collect like terms
3/5(25)-1/2(24)=3
15-12=3
3=3

Hope this helps------ptaylor