Question 1010053

{{{18x^3 + 24x^2 + 8x >= 0}}}


as you can see {{{18x^3 + 24x^2 + 8x}}} must be >=  {{{0}}}

so, for that reason you cannot use interval  ({{{-infinity}}},{{{-2/3}}}]U[{{{0}}},{{{infinity}}})

solutions are: {{{x>=0}}} and {{{x = -2/3}}}

and interval solution is:

[{{{-2/3}}}]U[{{{0}}},{{{infinity}}})