Question 86478
The given expression is: 


{{{ -3t + 3t^2 - 6t }}} 


Here, we observe that there are two temrs which contain t and one term that contain {{{t^2}}}. So grouping like terms, we get: 


{{{3t^2 - 9t}}} 


Here 3t can be taken out as the common factor. Hence, this cna be factored as: 


3t(t - 3) 


NOTE:  If the given quadratic is equated top zero then the value of t can be found out in the way as shown below. 


3t^2 - 9t = 0 


==> 3t(t - 3) = 0 


==> 3t = 0 OR t - 3 = 0 


==> t = 0  OR t = 3



Hence, the solution..


Regards