Question 1010039
given:

{{{slope= -1/3}}}; 

passing through ({{{9}}},{{{-1}}})=({{{x[1]}}},{{{y[1]}}})

an equation in point-slope form is:

{{{y-y[1] = m(x-x[1])}}}

{{{y -(-1) = -(1/3)(x-9)}}}

{{{y +1 = -(1/3)(x -9)}}}


 and slope-intercept form

{{{y=mx+b}}}....use given slope and point to find y-intercept {{{b}}}

{{{-1=-(1/3)*9+b}}}

{{{-1=-(1/cross(3)1)*cross(9)3+b}}}

{{{-1=-3+b}}}

{{{-1+3=b}}}

{{{b=2}}}


so, your line is: 

{{{y +1 = -(1/3)(x -9)}}}
or
{{{y=-(1/3)x+2}}} 


{{{ drawing( 600, 600, -10, 15, -10, 10, 
circle(9,-1,.12),locate(9,-1,p(9,-1)),
graph( 600, 600, -10, 15, -10, 10, -(1/3)x+2,-(1/3)(x -9)-1)) }}}