Question 1010001
Find the coordinates of the point that is equidistant from 
(-2,5), (8,5), and (6,7).
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From (-2,5)::sqrt[(x+2)^2+(y-5)^2]
From (8,5):: sqrt[(x-8)^2+(y-5)^2]
From (6,7):: sqrt[(x-6)^2+(y-7)^2]
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Equate rows 1 and 2::
(x+2)^2 = (x-8)^2
x^2 + 4x + 4 = x^2 - 16x + 64
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4x + 4 = -16x + 64
20x = 60
x = 3
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Solve for "y"::
Equate rows 2 and 3
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(x-8)^2 + (y-5)^2 = (x-6)^2 + (y-7)^2
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Since x = 3::
5^2 + y^2 - 10y + 25 = 3^2 + y^2 - 14y + 49
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4y + 50 = 58
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4y = 8
y = 2
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Ans: (3,2)
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Cheers,
Stan H.
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