Question 1009898
Slope of AG is  {{{(6-(-2))/(-5-(-1))=8/-4=-2}}};
The slope of any line perpendicular to AG is {{{1/2}}}, which is the negative reciprocal of  {{{-2}}}.


If you  just want to graph the line asked for, you have the given point H (8,5).  Plot H, and use the slope of {{{1/2}}} to find other points, and then draw the line through these points.


{{{y-5=(1/2)(x-8)}}}------applying the point-slope formula
{{{y-5=x/2-4}}}
{{{y=x/2+5-4}}}
{{{y=x/2+1}}}-------finishing equation in slope-intercept form


{{{graph(300,300,-4,8,-4,8,x/2+1)}}}