Question 1009827
.
Find the largest number of four digits divisible by 12 15 18 27 ?
------------------------------------------------------------------


The least common multiple of these numbers is {{{2^2*3^3*5}}} = 4*27*5 = 540.


So, the question is: what is the largest number of four digits divisible by 540? 


It is the whole part of the number {{{9999/540}}} = 18.517 multiplied by 540, i.e 18*540 = 9720.


<U>Answer</U>. 9720.