Question 1009863
y=  (x+2)^2/(e^x √(x^2+16))
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{{{y=  (x+2)^2e^(-x)*(x^2+16)^(-0.5)}}}
y' = {{{2(x+2)*e^(-x)*(x^2+16)^(-0.5) - (x+2)^2e^(-x)*(x^2+16)^(-0.5) -0.5*(x+2)^2e^(-x)*(x^2+16)^(-1.5)*2x}}}
= {{{2(x+2)*e^(-x)*(x^2+16)^(-0.5) - (x+2)^2e^(-x)*(x^2+16)^(-0.5) -x*(x+2)^2e^(-x)*(x^2+16)^(-1.5)}}}
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You can simplify it.
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