Question 1009845
The way I interpret the problem, I think your frustum looks like this(viewed from above):
{{{drawing(300,300,-35,35,-56,14,
line(-7.28,7.7,-4.5,0),
line(-4.5,0,4.5,0),
line(4.5,0,7.28,7.7),
line(7.28,7.7,0,11.94),
line(0,11.94,-7.28,7.7),
line(-31.6,-20.33,-19.5,-50),
line(-19.5,-50,19.5,-50),
line(19.5,-50,31.6,-20.33),
line(-31.6,-20.33,-7.28,7.7),
line(-19.5,-50,-4.5,0),
line(19.5,-50,4.5,0),
line(31.6,-20.33,7.28,7.7),
locate(-1.8,0,9cm),locate(-2.5,-46,37cm)
)}}}
Here is a front view, showing the cone that frustum was made from:
{{{drawing(400,300,-33,39,-4,52,
line(-31.6,0,31.6,0),
line(-7.28,35,7.28,35),
line(-31.6,0,-7.28,35),
line(31.6,0,7.28,35),
line(-4.5,35,-19.5,0),
line(4.5,35,19.5,0),
locate(-1.8,35,9cm),locate(-2.5,3,37cm),
green(triangle(-7.28,35,7.28,35,0,46.25)),
green(triangle(-4.5,35,4.5,35,0,46.25)),
locate(29,19,35cm),
arrow(32,20,32,35),arrow(32,15,32,0),
locate(36.3,24.6,h),
arrow(37,25.6,37,46.25),arrow(37,20.6,37,0),
green(arrow(8,35,8,46.25)),
green(arrow(8,46.25,8,35)),
locate(8.5,43,green(h-35cm))
)}}}
The triangles representing the front face of the pyramids in the from view picture are similar,
so their length measurements area proportional.
So {{{(h-35)/9=h/37}}}
{{{37(h-35)=9h}}}
{{{37h-1295=9h}}}
{{{37h-9h=1295}}}
{{{28h=1295}}}
{{{h=1295/28}}}-->{{{h=46.25}}}-->{{{h-35=11.25}}}
Now we can calculate
the volume of the large pyramid with a height of 46.25cm,
the volume of the small pyramid with a height of 11.25cm,
and the volume of the frustum (the difference between the volumes of those two pyramids.
The volume of a pyramid can be calculated as
{{{V=(1/3)*base_area*height}}} .
The area of a pentagon can be calculated as
{{{area=(1/4)side^2*5*tan(54^o)=approximately1.72*side^2}}} .
So the approximate volume of the smaller pyramid, in cubic cm is
{{{V[top]=(1/3)*1.75*9^2*11.25=522.45}}}
The approximate volume of the larger pyramid can be calculated similarly to be {{{36301.32}}} cubic centimeters.
Then the approximate volume of the frustum, in cubic cm is
{{{36301.32-522.45=35778.87}}} .
Because the {{{1.72}}} is not the exact value of the irrational quantity {{{5*tan(54^o)/4}}} ,
{{{35800cm^3}}} or {{{3.58*10^4}}}{{{cm^3}}} would be a more reasonable answer.