Question 1009924
Put over a common denominator
(x+x+3)/x(x+3)>=0
(2x+3)/x(x+3)>=0
Critical values are
0, -3, and -3/2; 
When x <-3, say -4, the numerator is negative and the denominator positive, so it doesn't work.
when x is -2, both are positive and it does work 
When x=-3/2, which is allowed, the value is 0.
When x is -1, it is +/-+, which doesn't work.
When x is >0 it does work.
(-3,-3/2] U [0,oo)
{{{graph(300,200,-10,10,-10,10,(1/(x+3))+(1/x))}}}
Note where the graph is positive