Question 1009837
this is an arithmetic sequence
the summation of the first n terms = (n/2)(2a + d(n-1)) where a is the first term and d is the difference between terms
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In our problem, n = 40, d = 5 and a = -3
summation of first 40 terms = (40/2)(2*(-3) + 5(40-1)) = 3780