Question 1009826
{{{log((3x-1))-log((2))=3}}}


What base, b ?


{{{log(((3x-1)/(2)))=3}}}


{{{b^3=(3x-1)/2}}}


{{{2b^3=3x-1}}}


{{{3x=1+2b^3}}}


{{{x=(2b^3+1)/3}}}
You must know the log base to finish for a value of x.