Question 1009766
The height is 4sqrt(3) inches
Each side is 8 inches
the altitude bisects the base, so there are two triangles with common height, hypotenuse 8, and short leg 4.
4^2+x^2=8^2
16+x^2=64
x^2=48
x=4 sqrt (3), altitude
Area is (1/2)bh=(1/2)(8)(4 sqrt(3))=16 sqrt (3) sq in.