Question 1009757

Hello
Please help me solve this problem 
How do I factorize completely: 

{{{x^5y-xy}}}

and also 

{{{5a^3-10a^2+3a-6}}}
<pre>{{{x^5y - xy}}}
{{{xy(x^4 - 1)}}} ----------------- Factoring out GCF, xy
{{{xy(x^2 - 1)(x^2 + 1)}}} --------- Factoring difference of 2 squares: {{{x^4 - 1}}} 
{{{highlight_green(xy(x - 1)(x + 1)(x^2 + 1))}}} ---- Factoring out difference of 2 squares: {{{x^2 - 1}}}

and also 

{{{5a^3 - 10a^2 + 3a - 6}}}
<u>5a<sup>3</sup> - 10a^2</u> <u>+ 3a - 6</u> ------- Grouping expressions to be factored
{{{5a^2(a - 2) + 3(a - 2)}}}
{{{highlight_green((5a^2 + 3)(a - 2))}}}