Question 86427
{{{f(x)=(4x-7)/(x^2+5x+4)}}}
For what values of x does f(x) approach infinity?
Rewrite the equation, factoring the denominator
{{{f(x)=(4x-7)/(x + 4)(x + 1)}}}
The denominator is zero for x=-4 and x=-1
That is when f(x) approaches infinity, so those
are the vertical asymptotes