Question 1009703
If the average of 7 distinct odd numbers is 39, the smallest number is 31 and the largest number is 53, what is the number in the middle?
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7*39 = 273
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273 - (31+53) = 189
31 < 5 odd numbers < 53 with a sum of 189
--> 33, 35, 37, 39, 41, 43, 45, 47, 49, 51
Several combinations are possible.
eg
33 + 35 + 37 + 39 + 45 = 189