Question 1009683
Same as {{{2x^2-10x+2y^2+6y=1}}}
{{{2(x^2-5x)+2(y^2+3y)=1}}}
Complete the squares for the x and the y, and continue.


{{{(x^2-5x)+(y^2+3y)=1/2}}}


{{{(x^2-5x+(5/2)^2)+(y^2+3y+(3/2)^2)=1/2+(5/2)^2+(3/2)^2}}}


Can you continue from there?