Question 1009655
2x-3y=16 where x=3y+11, so let's substitute in the equation:
2(3y+11)-3y= 16
6y+22-3y= 16 Simplify y on left and subtract 22 from both sides:
3y= -6 Divide both sides by 3
y= -2 Let's plug it in the equation and find x:
-------------------------------------
2x-3(-2)= 16
2x+6= 16
2x= 10
x= 5
-------------------------------
So there you have it:
y= -2
x= 5