Question 1009549
I could give you the answer, but let's explore what happens if we substitute 2l, 2w, and 2h in for l, w, and h in the formula
A = 2lw + 2lh + 2wh
We get
A' = 2(2l)(2w) + 2(2l)(2h) + 2(2w)(2h)
A' = 8lw + 8lh + 8wh
which is exactly FOUR times the original area A.