Question 1009517
I need to find the solution set

Log 2^(5x+8)=2 
<pre>{{{log 2^(5x + 8) = 2}}}
{{{2^(5x + 8) = 10^2}}} 
{{{log 2^(5x + 8) = log 10^2}}} -------  Taking LOG of each side
(5x + 8) {{{"*"}}} log 2 = 2 {{{"*"}}} log 10
(5x + 8) {{{"*"}}} log 2 = 2
{{{5x + 8 = 2/log 2}}}
5x + 8 = 6.643856
5x = 6.643856 – 8
5x = - 1.356144
{{{x = - 1.356144/5}}}, or {{{highlight_green(- 0.27123)}}}