Question 1009440
Complete the square to find the center of the circle,
{{{2x^2 + 2y^2 + 10x – 6y – 55 = 0}}}
{{{2x^2+10x+2y^2-6y-55=0}}}
{{{x^2+5x+y^2-3y-55/2=0}}}
{{{(x^2+5x+25/4)+(y^2-3y+9/4)-55/2-25/4-9/4=0}}}
{{{(x+5/2)^2+(y-3/2)^2=110/4+25/4+9/4}}}
{{{(x+5/2)^2+(y-3/2)^2=144/4}}}
{{{(x+5/2)^2+(y-3/2)^2=36}}}
The circle is centered at ({{{-5/2}}},{{{3/2}}}) so it is {{{5/2}}} from the y-axis.